Jackson Whipps Showalter vs. Albert Beauregard Hodges Match
? 1894 - 4/10/1894


           1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7
Showalter  1  1  0  0 0 1 1 1 0  0     1  +7-6=4
Hodges     0  0  1  1 1 0 0 0 1  1     0  +6-7=4



  • Showalter finished third at New York, 1893, behind 20 year old Harry Nelson Pillsbury, and Albert Beauregard Hodges. Pillsbury had no interest in challenging him to a match, but Hodges did.

  • The match was to be won by the first player to win 7 games. Stakes were $100 per side. Showalter was White in the odd numbered games. Play took place at the Manhattan Chess Club.

  • Games 15 and 16 were both decisive, one being won by Showalter, the other by Hodges. I'm just not sure which was which.

  • When the score was tied at 6-6, both players agreed to play a second match later, regardless of who won the 7th and deciding game.

    # Opening Ended
    1 Ruy Lopez ?
    2 Queen Pawn Opening ?
    3 French 2/17/1894
    4 Queen Pawn Opening ?
    5 Sicilian Defense 2/19/1894
    6 Queen Pawn Opening 2/21/1894
    7 Ruy Lopez 3/4/1894
    8 Stonewall 3/7/1894
    9 Sicilian Defense 3/13/1894
    10 Queen's Gambit Declined 3/19/1894
    11 ? ?
    12 Queen's Gambit Declined 3/23/1894
    13 ? ?
    14 Colle Opening 4/1/1894
    15 ? ?
    16 ? ?
    17 Ruy Lopez 4/10/1894

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